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General Logarithmic & Exponential Functions?

0 votes
∫ 2^5x+1 dx

I have my u=5x+1
asked Apr 22, 2013 in CALCULUS by abstain12 Apprentice

1 Answer

0 votes

ʃ25x + 1 dx

let u = 5x + 1

Apply derivative to each side

du = 5dx

Substitute dx   =(1 / 5) du

(1 / 5) ʃ 2u du = (1 / 5 ) 2u / log2 + C

                       =2u / 5log2 + c

Substitute u = 5x + 1

                       = 25x + 1 / 5log2 + C

                       =25x + 1 / log25 + C.

answered Apr 22, 2013 by diane Scholar

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