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Use implicit differentiation to find an equation of the tangent line to the graph at the given point.

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Use implicit differentiation to find an equation of the tangent line to the graph at the given point.

x + y - 1 = ln (x^2 + y^2),          (1, 0)
asked Jan 29, 2015 in CALCULUS by anonymous

1 Answer

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Step 1:

The equation is and the point is .

The slope of the tangent line is equal to the derivative of the function at .

Apply derivative on each side with respect to .

image

image

Step 2:

Slope at the point , Substitute  in image.

image

Point-slope form of line equation .

Substitute point and slope in the above equation.

Tangent line equation is image.

Solution:

Tangent line equation is image.

answered Jan 29, 2015 by Lucy Mentor
edited Jan 29, 2015 by Lucy

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