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help - application-integrals

0 votes

asked Jun 2, 2015 in CALCULUS by anonymous

3 Answers

0 votes

1.

(a)

Step 1 :

The function is on the interval .

Average value of the function on is defined as .

Here .

Average value of is

.

Average value of the function on is .

Solution :

Average value of the function on is .

answered Jun 2, 2015 by sandy Pupil
0 votes

(b)

Step 1 :

The function is on the interval .

Average value of the function on is defined as .

Here .

Average value of is

Consider .

Differentiate with respect to .

Substitute and in equation (1).

image

Step 2 :

Power rule of integration : .

Substitute in above equation.

image

.

Average value of the function on is .

Solution :

Average value of the function on is .

answered Jun 2, 2015 by sandy Pupil
edited Jun 2, 2015 by sandy
0 votes

(2)

Step 1 :

The function is on the interval .

Mean Value Theorem : .

Here .

Average value of is

 

.

Step 2 :

The function in terms of is .

Substitute in .

and .

The value of is .

Solution :

The value of is .

answered Jun 2, 2015 by sandy Pupil

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