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help? power-series?

0 votes

asked Jun 2, 2015 in CALCULUS by anonymous

2 Answers

0 votes

1)

Step 1:

The series is .

Find the interval of convergence using ratio test.

Ratio test :

(i) If , then the series is absolutely convergent.

(ii) If or , then the series is divergent.

Here and .

Find

By the ratio test, the series is convergent when .

Therefore, interval of convergence is  , but need to check convergence at end points also.

Step 2:

Substitute in the series .

Above series is a alternating series in which   term is  and for all .

.

Thus, the series is convergent at by alternating series test.

answered Jun 2, 2015 by cameron Mentor

Step 3:

Substitute in the series .

Above series is a p- series with p=1.

The p- series  is convergent if and divergent if .

Hence the series is divergent at by p- series test.

The interval of convergence is .

Solution:

The interval of convergence is .

0 votes

2)

Step 1:

The series is .

Find the interval of convergence using ratio test.

Ratio test :

(i) If , then the series is absolutely convergent.

(ii) If or , then the series is divergent.

Here and .

Find .

By the ratio test, the series is convergent when .

Therefore, interval of convergence is  , but need to check convergence at end points also.

Step 2:

Substitute in the series .

Consider  .

Find .

Doesnot exist.

The series is divergent by the test of divergence.

Thus, the series is divergent at by the test of divergence.

answered Jun 2, 2015 by cameron Mentor
edited Jun 2, 2015 by cameron

Continued....

Step 3:

Substitute in the series .

The series is divergent by the test of divergence.

Thus, the series is divergent at by the test of divergence.

The interval of convergence is .

Solution:

The interval of convergence is .

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