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Calculus, 8th Edition,stewart; page 21 problem 51

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Find an expression for the function whose graph is the given curve.

The line segment joining the points (1, -3) and (5, 7)
asked Jul 27, 2015 in CALCULUS by anonymous
reshown Jul 27, 2015 by bradely
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1 Answer

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Step:1

The points are (1, -3) and (5, 7).

Standard form of line equation using the points (x_{1}, y_{1}) and (x_{2}, y_{2}) is  (y-y_{1})=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1}).

Substitute (x_{1}, y_{1})=(1, -3) and (x_{2}, y_{2})=(5, 7) in the line equation.

(y-(-3))=\frac{7-(-3)}{5-1}(x-1)

(y+3)=\frac{7+3}{4}(x-1)

(y+3)=\frac{10}{4}(x-1)

(y+3)=\frac{10}{4}x-\frac{10}{4}

y=\frac{5}{2}x-\frac{5}{2}-3

y=\frac{5}{2}x-(\frac{5}{2}+3)

y=\frac{5}{2}x-(\frac{5+6}{2})

y=\frac{5}{2}x-(\frac{11}{2}).

Solution:

The function is f(x)=\frac{5}{2}x-(\frac{11}{2}).

answered Jul 28, 2015 by dozey Mentor

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