# AC Problem Power

(a)

Maximum Power Transfer:

For any power source, the maximum power transferred from the power source to the load is when the resistance of the load is equal to the equivalent or input resistance of the power source .

Apply Thevinin's theorem:

Find Thevinin's equivalent impedance.

2.Open Current Sources and Short Voltage Sources.

3.Calculate the Open Circuit Impedance. This is the Thevenin Impedance ().

Redraw the circuit:

Observe the circuit:

can be written in complex form as .

can be written in complex form as

(b)

Step 1:

Find Thevenin's voltage.

Use Superposition principle to calculate volatge across A and B.

Super Position Theorem :

Take one current source at a time and replace all other with short or internal resistance.

in complex form can be written as .

Apply current divider rule: .

Find the total impdenace .

is in parallel to .

is in series to .

Current divider rule:

Find the voltage drop across the impedance Z.

V.

Step 2:

Take another voltage source at a time and replace all other with open or internal resistance.

in complex form can be written as

Apply KVL to loop 1:

Find the voltage drop across the impedance Z.

V.

Step 3:

By superposition principle :

The Voltage acoss the terminal A and B is .

Thevinins equivalent voltage is

Draw the equivalent circuit.

Power in the circuit is .

Power in the circuit is 17.89 W.

Solution:

Power in the circuit is 17.89 W.