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AC Problem Power

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asked Dec 16, 2015 in ELECTRICAL ENGINEERING by anonymous

2 Answers

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(a)

Maximum Power Transfer:

For any power source, the maximum power transferred from the power source to the load is when the resistance of the load image is equal to the equivalent or input resistance of the power source image.

Apply Thevinin's theorem:

Find Thevinin's equivalent impedance.

1.Open the load resistor.

2.Open Current Sources and Short Voltage Sources.

3.Calculate the Open Circuit Impedance. This is the Thevenin Impedance (image).

Redraw the circuit:

image

Observe the circuit:

image

image can be written in complex form as image.

image

image can be written in complex form as image

image

answered Dec 16, 2015 by Lucy Mentor
0 votes

(b)

Step 1:

Find Thevenin's voltage.

Use Superposition principle to calculate volatge across A and B.

Super Position Theorem :

Take one current source at a time and replace all other with short or internal resistance.

image

image in complex form can be written as .

Apply current divider rule: .

Find the total impdenace .

 is in parallel to .

 is in series to .

Current divider rule:

Find the voltage drop across the impedance Z.

 V.

Step 2:

Take another voltage source at a time and replace all other with open or internal resistance.

image

image in complex form can be written as 

Apply KVL to loop 1:

Find the voltage drop across the impedance Z.

 V.

Step 3:

By superposition principle : 

The Voltage acoss the terminal A and B is .

Thevinins equivalent voltage is 

Draw the equivalent circuit.

image

Power in the circuit is image.

image

Power in the circuit is 17.89 W.

Solution:

Power in the circuit is 17.89 W.

answered Dec 16, 2015 by Lucy Mentor
edited Dec 16, 2015 by Lucy

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