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Matrix

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-4y+3x=-1                       -4x+3y= -2

2x-3y=-3                          -2x-3y=4

the two system of equations above share the same common coefficient matrix a. Because of this, we can use the same inverse to solve both systems of equations as outlined below.

a) find the inverse of the common coefficient matrix A.    

 A^-1

b) find the solutions to th 2 systems by evaluating A^-1B where B represents the right hand side(ie:B=[-1,-3] for the first and B=[-2,4] for the second system.

first system: x= ____________,y=______________

second system x=__________,y=__________
asked Jul 7, 2016 in PRECALCULUS by anonymous
reshown Jul 8, 2016 by goushi

2 Answers

0 votes

(1)

Step 1:

The first system equations are image

Write the equations into matrix form , where is coefficient matrix,

is variable matrix and is constant matrix.

image

Definition of inverse matrix :

If is an then , where .

Let image, then image.

image

, then has an inverse.

(a)

Find the inverse matrix image.

image

image

(b)

Find image values of first system.

image

Substitute image.

image

Solution:

(a) The inverse matrix is image

(b) The value of first system is image.

answered Jul 8, 2016 by Anney Mentor
0 votes

(2)

Step 1:

The second system equations are image

Write the equations into matrix form , where is coefficient matrix,

is variable matrix and is constant matrix.

image

Definition of inverse matrix :

If is an then , where .

Let image, then image.

image

, then has an inverse.

(a)

Find the inverse matrix image.

image

image

(b)

Find image values of second system.
 

image

Substitute image.

image

Solution:

(a) The inverse matrix is image

(b) The value of second system is image.

answered Jul 8, 2016 by Anney Mentor

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