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Evaluate the integral!!!!!!!!!!!!!!!!!!!!!!!!!!

0 votes
Evaluate the integral
∫ cos3 5x dx
asked Jun 22, 2013 in CALCULUS by rockstar Apprentice

1 Answer

0 votes

∫ cos3 5x dx

=∫ cos2 5x*cos5x dx

=∫ (1-sin2 5x)*cos5x dx

sin5x=t

dt/dx=5cos5x

dt/5=cos5xdx

=(1/5)∫(1-t2)*dt

=(1/5)(t-t^3/3)+c

=(1/5)(sin(5x)-sin^3(5x))+c

 

 

answered Jun 23, 2013 by bradely Mentor

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