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Calculus help 1 problem?

0 votes

Fundamental theorem of Calculus:

(pi/4)
∫(1-sin2t)^3cos2tdt
0

Correct Answer 1/8

I'm lost how would I solve this?

asked Jun 28, 2013 in CALCULUS by payton Apprentice

1 Answer

0 votes

image

Where  1- sin2t = x

 - 2cos(2t) dt = dx

  cos2t dt = - 1/2 dx

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Therefore x = 1- sin2t

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Apply fundamental therom

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Apply limits on both sides

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Since sin(π/2) = 1 and sin(0) = 0

image

image.

answered Jun 28, 2013 by goushi Pupil

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