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Find two solutions of each equation? Give your anwser in radians (0 < \theta < 2 π). Dont use no caculator.

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Find two solutions of each equation? Give your anwser in radians (0 < \theta < 2 π). Dont use no caculator.

tan \theta= 1

cot \theta= - \sqrt{}3

 

asked Sep 5, 2018 in TRIGONOMETRY by rockstar Apprentice
reshown Sep 5, 2018 by bradely

1 Answer

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tan \theta= 1

tan \theta= tan(π/4)

\theta= nπ+π/4

At n = 1

\theta=π+π/4 =5π/4

cot \theta=-√3

tan \theta=-1/√3

tan \theta=tan(-π/6)

\theta= nπ-π/6

At n = 1

\theta= π-π/6=5π/6

At n = 2

\theta= 2π-π/6=11π/6

\theta=5π/6 and 11π/6

answered Sep 14, 2018 by lilly Expert
reshown Sep 14, 2018 by bradely

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