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Solve the equation on the interval

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Cos^2theta+2cos theta+1=0
asked May 6, 2019 in TRIGONOMETRY by anonymous
reshown May 7, 2019 by bradely

1 Answer

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cos^2theta+2cos theta+1=0

Let cos theta = x

x^2+2x+1=0

solve the quadratic equation

(x+1)^2=0

x=-1

cos theta =-1

cos theta = cos (pi)

Write the general solution

theta = 2npi+pi =pi(2n+1)

answered May 7, 2019 by homeworkhelp Mentor

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