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integration!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

0 votes

asked Jul 8, 2013 in CALCULUS by harvy0496 Apprentice

1 Answer

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image

Apply integration  each  term  by term

                             4

=(5x^3/3-6x^2/2+6x)

                                      0

Apply  limits

=5(4^3/3)-6(4^2/2)+6(4)+C

=5(64/3)-6(8)+24+C

=(320/3)-48+24+C

=(320/3)-24+C

=248/3+C

The  solution is 248/3+C

 

answered Jul 9, 2013 by bradely Mentor

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