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Find the maximum and minimum values of the function

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Find the maximum and minimum values of the function f(θ) = 5√2θ − 5 sec on the interval 0, π/3  (Round your answers to three decimal places.) maximum f(θ) =  minimum f(θ) =
asked Jul 13, 2013 in PRECALCULUS by anonymous Apprentice

1 Answer

0 votes

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Substitute x in the place of image

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Multiply each side by negative one

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Now use quadratic formula

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But the range of sinx is [ 1 , -1 ] we can have only

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By the second derivative it is locally minimum at

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Substitute in given f(x)

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Now check the end points f(0) = -5 and

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= -2.595

So the maximum value of  

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= -1.517

And the minimum value is f(o) = -5

answered Jul 16, 2013 by jouis Apprentice

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