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Verify this trigonometric equation help please!

0 votes

-tan^2x+sec^2x=1

asked Jul 14, 2013 in TRIGONOMETRY by anonymous Apprentice

1 Answer

0 votes

-tan^2x+sec^2x=1

tanx=sinx/cosx

secx=1/cosx

=-(sinx/cosx)^2+(1/cosx)^2

=(-sin^2x+1)/cos^2x

Here -sin^2x+1=cos^2x

=cos^2x/cos^2x

=1

answered Jul 14, 2013 by bradely Mentor

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