Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,043 users

could somebody please check my answer if it is correct.

0 votes

the question is: Find the value of f'(-2) if f(x)=(x^2+2) sin(4-3x)

asked Jul 19, 2013 in CALCULUS by anonymous Apprentice

1 Answer

0 votes

f(x)=(x^2+2) sin(4-3x)

f'(x)=(x^2+2)(-3)cos(4-3x)+2xsin(4-3x)

        =-3(x^2+2)cos(4-3x)+2xsin(4-3x)

substitute x=-2

f'(-2)=-3((-2)^2+2)cos(4-3(-2))+2(-2)sin(4-3(-2))

           =-18cos(10)-4sin(10)

          =-18cos(10*180/pi)-4sin(10*180/pi)

          =-18*-0.84-4*-0.545

          =15.12+2.18

           =17.3

 

answered Jul 19, 2013 by bradely Mentor

Related questions

asked Jul 18, 2014 in PHYSICS by anonymous
asked Jan 13, 2017 in ALGEBRA 2 by anonymous
asked Dec 28, 2016 in ALGEBRA 2 by anonymous
...