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graph this? (find the domain and range, show 3 coordinates on the graph please)

0 votes
y=-sqrt(x-1)
asked Aug 1, 2013 in CALCULUS by angel12 Scholar

1 Answer

0 votes

The function is y = - √(x - 1).

Squaring on both sides.

y2 = x - 1

Add 1 to each side.

x = y2 + 1.

The above equation represents a parabola.

Make the table of values to find ordered pairs that satisfy the equation.

Choose values for y and find the corresponding values for x.

y

x = y2 + 1

(x, y)

- 2

x = (- 2)2 + 1 = 4 + 1 = 5

(5, - 2)

- 1

x = (- 1)2 + 1 = 1 + 1 = 2

(2, - 1)

0

x = (0)2 + 1 = 0 + 1 = 1

(1, 0)

1

x = (1)2 + 1 = 1 + 1 = 2

(2, 1)

2

x = (2)2 + 1 = 4 + 1 = 5

(5, 2)

1.Draw a coordinate plane.

2.Plot the coordinate points.

3.Then sketch the graph, connecting the points with a smooth curve.

graph the equation x=y^2

Since x can be any real number, there is an infinite number of ordered pairs that can be graphed. All of them lie on the graph shown.

Notice that every real number is the x - coordinate of some point on the graph, so the domain is [1 , infinity).

But, only real numbers less than or equal to 0 are y - coordinates of points on the graph. So the range is {y | y ≤ 0}.

answered Aug 7, 2014 by lilly Expert

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