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find the inclination angle

0 votes

Find the inclination (in radians and degrees) of the line

6x-2y+8=0

asked Oct 30, 2013 in GEOMETRY by skylar Apprentice

1 Answer

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Write the line equation in slope-intercept form y = mx + b, m is slope and b is y-intercept.
6x - 2y+8 = 0

Add 2y to each side

6x + 8 = 2y

Divide each side by 2

y = 3x +4

Slope = 3

m = 3

Re call m = tanθ, where θ is inclination angle

m = tanθ = 3

θ = 71° or  -161° and 71 × ∏/180 or 161× ∏/180

substitute the value of ∏ = 3.14

θ = 71° or  -161° and 71 × 3.14/180 or 161× 3.14/180         

θ = 71° or  -161° and 1.238(radians) or 2.808(radians)

Since the slope is positive Tangent sign should be positive, so the line passes through the I and II quadrant.

So, inclination angle is 71°.

answered Oct 30, 2013 by steve Scholar

Therefore, the inclination angle is 71.560 (or) 1.248radians.

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