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2x^2-27=0 solving quadratic Equations

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solving quadratic Equations
asked Nov 15, 2013 in ALGEBRA 1 by dkinz Apprentice

1 Answer

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Given quadratic equation is 2x^2 - 27 = 0

2x^2 = 27

x^2 = 27/2

x^2 = 13.5

x = sqrt(13.5)

x = 3.67

 

answered Nov 16, 2013 by jouis Apprentice

The equation 2x2 - 27 = 0

2x2 = 27

x2 = 27/2

x= 13.5

Apply squre root on each side.

x = ± √(13.5)

x = ± 3.67

Solutions are x = 3.67 and x = -3.67.

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