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Asymptote of the

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asked Nov 17, 2013 in PRECALCULUS by abstain Rookie

1 Answer

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To find the  vertical asymptote ,set denominator equal to zero and solve.



No solution for this equation.

Therefore, the vertical asymptote is none.

Calculate the  horizontal asymptote ,

lim         x^2/(x^2+9)

x---> ∞


lim         x^2/x^2(1+9/x^2)

x---> ∞

Cancel common terms


im         1/(1+9/x^2)

x---> ∞


Therefore, the horizontal asymptote is y=1.

answered Nov 17, 2013 by bradely Mentor

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