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Find the slope of the tangent curve

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y=7/x^(1/2)
asked Nov 19, 2013 in CALCULUS by dkinz Apprentice

1 Answer

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y = 7/x^(1/2)

y = 7x^-1/2

Apply dervative on each side with respect of x.

Recall the formulad/dx(x^n) = nx^n-1

dy/dx = 7*-1/2x^(-1/2-1)

dy/dx = (-7/2)x^-3/2

dy/dx = (-7/2)(x^3)^-1/2

Slope of tangent given curve is dy/dx = (-7/2√x^3)

answered Feb 3, 2014 by david Expert

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