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What are the steps to proving the following Trigonometry identity?

0 votes

sec(x)-tan(x)=(cos(x)/1+sin(x))

asked Nov 20, 2013 in TRIGONOMETRY by rockstar Apprentice
reshown Nov 20, 2013 by goushi

1 Answer

0 votes

sec(x)-tan(x) = cos(x)/1+sin(x)

We know that secx = 1/cosx and tanx = sinx/cosx

Left hand side

= 1/cos(x)-sin(x)/cos(x)

= 1-sin(x)/cos(x)

Multiple by 1+sin(x)/1+sin(x)

= (1-sin(x)/cos(x))(1+sin(x)/1+sin(x))

= 1^2-sin^2(x)/cos(x)(1+sin(x))

= cos^2(x)/cos(x)(1+sin(x))

= cos(x)/1+sin(x)

= Right hand side

answered Nov 21, 2013 by william Mentor

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