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g(x)=√(x)sinx

0 votes

Trying to find the derivative using the product rule. Would appreciate if steps are explained.

derivative
product-rule

asked Nov 21, 2013 in CALCULUS by mathgirl Apprentice

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1 Answer

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g(x) = √(x)sinx

Apply derivative with respect of x.

= d/dx(√(x)sinx

d/dxuv = udv/dx+vdu/dx

=√(x)d/dx(sinx)+sinxd/dx(√x)

=√(x)cosx+sinx1/2√(x)

answered Nov 21, 2013 by william Mentor

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