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how do you solve (x-1)(√3-x) on the integral 1 to 3

0 votes
can you solve (2sinx+sin2x)dx on the integral of 0 to π

 

asked Dec 9, 2013 in CALCULUS by harvy0496 Apprentice

2 Answers

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Given 2sinx+sin2x

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answered Jan 23, 2014 by david Expert
0 votes

(1).

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The solution is (6√3 - 14)/3.

answered Aug 19, 2014 by casacop Expert

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