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solve 3-r/2=r-2/3

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solve and check, 3-r/2=r-2/3.

asked Feb 19, 2014 in ALGEBRA 1 by abstain12 Apprentice

1 Answer

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Given 3-r/2 = r-2/3

Add 2/3 to each side.

3-r/2+2/3 = r-2/3+2/3

3+2/3-r/2 = r

11/3-r/2 = r

Add r/2 to each side.

11/3-r/2+r/2 = r+r/2

11/3 = 3r/2

Multiple to each side by 2.

2(11/3) = 2(3r/2)

22/3 = 3r

Divide to each side by 3.

22/3*3 = 3r/3

r = 22/9

Check

substitute the r value in 3-r/2 = r-2/3

3-22/18 = 22/9-2/3

(54-22)/18 = 16/9

16/9 = 16/9

answered Feb 19, 2014 by david Expert

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