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x+4y-z=1, 3x-y+8z=0 and x+4y-z=10

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system of equations.

asked Feb 20, 2014 in ALGEBRA 2 by linda Scholar

1 Answer

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Given equations x+4y-z = 1 ---> (1)

3x-y+8z = 0 ---> (2)

x+4y-z = 10 ---> (3)

Observe the given equations (1)& (3) are parallel.

Parallel planes are does not intersect.

In this case there is no solution.

answered Feb 20, 2014 by david Expert

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