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passing through the points ( 2,3) & ( 4,9) using y=mx+b

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slope intercept form.

asked Feb 20, 2014 in ALGEBRA 2 by payton Apprentice

2 Answers

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Given points are

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answered Feb 20, 2014 by friend Mentor
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Slope-intercept form line equation is y = mx + b, where m is slope and b is y-intercept.

Let the points are (x₁, y₁) = (2, 3) and (x₂, y₂) = (4, 9).

Slope (m) = [(y₂ - y₁)/(x₂ -x₁)]

m = [(9 - 3)/(4 - 2)]

m  = 6/2

m = 3.

Now, the line equation is y = 3x + b.

Find the y - intercept by substituting any point in the line equation say (x, y) = (2, 3).

3 = (3)(2) + b

b = 3 - 6

b = - 3.

The line equation required is y = 3x - 3.

answered Aug 28, 2014 by lilly Expert

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