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solve the equatoion

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4(x+1)^2=100.
asked Mar 11, 2014 in ALGEBRA 1 by skylar Apprentice

1 Answer

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The equation is 4(x + 1)^2 = 100.

Apply formula : (a + b )^2 = a ^2 + 2ab + b ^2.

4(x ^2 + 2x + 1) = 100

Divide each side by 4.

x ^2 + 2x + 1 = 100/4

x ^2 + 2x + 1 = 25

Subtract 25 from each side.

x ^2 + 2x + 1 - 25 = 0

x ^2 + 2x - 24= 0

x ^2 + 6x - 4x - 24= 0

Factor : (x + 6)(x - 4) = 0.

Apply zero product property.

(x + 6) = 0 (or) (x - 4) = 0

x = 4 (or) - 6.

Solution is x = 4 (or) - 6.

answered Mar 24, 2014 by dozey Mentor

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