Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

    
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

778,053 users

whats the nth term for

0 votes

2, 10, 24, 44, 70

asked Apr 26, 2014 in ALGEBRA 2 by anonymous

2 Answers

–1 vote

The sequence is 2, 10, 24, 44, 70, ..............

The formula 3n^2 - n generates the a sequence of numbers as follows :

n = 1            3n^2 - n = 3( 1 )^2 - 1 = 3 - 1 = 2

n = 2            3n^2 - n = 3( 2)^2 - 2 = 12 - 2 = 10

n = 3            3n^2 - n = 3( 3 )^2 - 3 = 27 - 3 = 24

n = 4            3n^2 - n = 3( 4 )^2 - 4 = 48 - 4 = 44

n = 5            3n^2 - n = 3( 5 )^2 - 5 = 75 - 5 = 70

etc.

So, the formula generates the sequence 2, 10, 24, 44, 70, .............. etc.

Therefore, the n th term of the given sequence is 3n^2 - n.

answered Apr 26, 2014 by lilly Expert
0 votes

Sequence : An ordered list of numbers (or) A sequence is a list of numbers in a particular order.

Series : The sum of an ordered list of numbers (or) A series is an indicated sum of the terms of a sequence.

Arithmetic Sequence : A sequence of numbers with a common difference between any two consecutive terms.

Arithmetic Series : The sum of terms in an arithmetic sequence.

Geometric Sequence : A sequence of numbers with a common ratio or multiplier between any two consecutive terms.

Arithmetic Series : The sum of terms in an geometric sequence.

The numbers are 2, 10, 24, 44, 70, .......... n.

The above numbers are do not follow the particular order, so this is not a sequence.

This is may be series.

To check the series is arithmetic or geometric as follows.

image

Here the common difference d2 = 6.

Arithmetic sequence :

image

Arithmetic series :

image

The sum Sn of the first n terms of an arithmetic series is given by image, where t1 = first term = 2, tn = last term = n and d = common difference = 6.

.

Check :

n = 1           s1 = 3n^2 - n = 3( 1 )^2 - 1 = 3 - 1 = 2.

n = 2           s2 = 3n^2 - n = 3( 2)^2 - 2 = 12 - 2 = 10.

n = 3           s3 = 3n^2 - n = 3( 3 )^2 - 3 = 27 - 3 = 24.

n = 4           s4 = 3n^2 - n = 3( 4 )^2 - 4 = 48 - 4 = 44.

n = 5           s5 = 3n^2 - n = 3( 5 )^2 - 5 = 75 - 5 = 70. etc.

 

answered Apr 28, 2014 by steve Scholar

Related questions

...