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(1/3)x+(x -20)°+(x -10)°+40°=360°? 

 

 

asked Sep 9, 2014 in PRECALCULUS by anonymous

1 Answer

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(1/3)x+(x -20)°+(x -10)°+40°=360°

(1/3)x+x-20+x-10+40 = 360

(1/3)x+2x+10=360

x(1/3 +2) = 350

x(7/3) =350

7x = 350× 3

x=1050/7

x=150°

answered Sep 9, 2014 by friend Mentor

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