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HELp Sin=6squarert 37/37 cos= -squarert37/37

0 votes

tan =? csc? sec? cot?

 

 

asked Oct 25, 2014 in PRECALCULUS by anonymous

1 Answer

0 votes

Given that image and image

Clearly sinθ value is positive and cosθ is negative which means that that θ lies in second coordinate.

(i)

image

image

(ii)

image

image

(iii)

image

(iv)

image

answered Oct 25, 2014 by dozey Mentor
edited Oct 25, 2014 by dozey

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