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Equation of a circle question?

0 votes
Write the equation of a circle with a center at (2.5, –3.5) and a diameter of 12.
Answer

(x + 2.5)2 + (y – 3.5)2 = 12

(x – 2.5)2 + (y + 3.5)2 = 36

(x + 2.5)2 + (y – 3.5)2 = 36

(x – 2.5)2 + (y + 3.5)2 = 144
asked Oct 30, 2014 in ALGEBRA 2 by anonymous

1 Answer

0 votes

Standard form of circle (x - h)2 + (y - k)2 = r2

Where (h , k) is center of circle and r is radius.

The centre of circle (h, k) = (2.5, - 3.5)

And the diameter = 12

Radius r = d/2

r = 12/2

r = 6

Substitute r = 6 and (h , k) = (2.5, - 3.5) in Standard form.

(x - 2.5)2 + (y - (- 3.5) ]2 = 62

The circle equation is (x - 2.5)2 + (y + 3.5)2 = 36.

Second option is correct.

answered Oct 30, 2014 by david Expert

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