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Suppose that x = x(t) and y=y(t) are both functions of t.

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 If y = 4 x^2 - 1, and dx/dt = 3 when x = 11, what is dy/dt?

asked Nov 11, 2014 in CALCULUS by anonymous

1 Answer

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Given data :

y = 4 x² - 1

dx/dt = 3

x = 11

dy/dt = ?

y = 4 x² - 1

Apply derivative with respect to t both sides.

dy/dt = 4(2x)dx/dt

dy/dt = 8x*(dx/dt)

Substitute :

x = 11and dx/dt = 3

dy/dt = 8*11*3

dy/dt = 264

answered Nov 11, 2014 by Shalom Scholar

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