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Simplify so that no quotients appear in the final expression

0 votes

cos^2x-sin^2x / sinxcosx'?

answer choices: 

a. sinx-cosx 
b. tanx-cotx 
c. cotx-tanx 
d. -tanx(cotx) 
e. tanx 
f. cotx(tanx) 

asked Dec 9, 2014 in TRIGONOMETRY by anonymous

1 Answer

0 votes

The expression (cos2x - sin2x)/(sinx cosx)

= [cos2x/(sinx cosx)] -[sin2x/(sinx cosx)]

= (cosx/sinx) - (sinx/cosx)

= cotx - tanx

(cos2x - sin2x)/(sinx cosx) = cotx - tanx

Option c is correct.

answered Dec 9, 2014 by david Expert

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