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Evaluate the integral. sin^7 θ cos^5 θ dθ [0, pi/2]?

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Evaluate the integral. sin^7 θ cos^5 θ dθ [0, pi/2]?

asked Feb 11, 2015 in CALCULUS by anonymous
reshown Feb 11, 2015 by goushi
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1 Answer

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tep 1:

The integral is image.

Re-write the integral.

image

Trigonometric identities : image.

image

image

Solution:

image

answered Feb 17, 2015 by Lucy Mentor

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