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HELP19

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asked Jul 6, 2015 in ELECTRICAL ENGINEERING by anonymous
recategorized Jul 8, 2015 by bradely

4 Answers

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3.1.

3.1.1)

P-n junction diode:

D. It has heavily doped p-type and n-type regions separated by an intrinsic region.

3.1.2)

Varactor diode:

A. Its operation depends on the capacitance that exist at the p-n junction which is reverse biased.

3.1.3)

Tunnel diode:

C. It has a negative resistance region where an increase in terminal voltage results in reduction in the diode current.

3.1.4)

Zener diode:

B. It permits the current to flow in the forward bias direction but it will also flow in the reverse bias when  the voltage is above the breakdown voltage.

Solution:

3.1.1) P-n junction diode: D.

3.1.2) Varactor diode: A.

3.1.3) Tunnel diode: C.

3.1.4) Zener diode: B.

answered Jul 8, 2015 by cameron Mentor
0 votes

(3.3.1)

Find the secondary peak voltage.

Observe the waveform obtained from half wave rectifier.

Secondary peak voltage is Vp = 14 V.

Solution:

Secondary peak voltage is Vp = 14 V.

answered Jul 9, 2015 by yamin_math Mentor
0 votes

(3.3.2)

Find average output voltage.

Observe the waveform obtained from half wave rectifier.

Secondary peak voltage is Vp = 14 V.

Average output voltage is image.

image

Average output voltage is 4.456 V.

Solution:

Average output voltage is 4.456 V.

answered Jul 9, 2015 by yamin_math Mentor
0 votes

(3.3.3)

Find secondary RMS voltage.

Observe the waveform obtained from half wave rectifier.

Secondary peak voltage is Vp = 14 V.

Secondary RMS voltage is image.

image

Secondary RMS voltage is 7 V.

Solution:

Secondary RMS voltage is 7 V.

answered Jul 9, 2015 by yamin_math Mentor

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