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Physics Homework Question?

0 votes

An ideal gas expands isothermally, performing 4.80×103 J of work in the process.

Part A

Calculate the change in internal energy of the gas.
 
Part B
Calculate the heat absorbed during this expansion.

 

asked Nov 29, 2015 in PHYSICS by anonymous

2 Answers

0 votes

In a isothermal process temeprature is constant.

It means ΔU =0.

change in internal energy of the gas is zero

From the firstlaw of thermodynamics

Q = ΔU + W

    =0 +4.80×10^3

    = 4.80×10^3 J

answered Nov 29, 2015 by anonymous
0 votes

(a)

For an isothermal process, temperature is constant.

Isothermal process: image.

Change in internal energy of the gas is 0.

(b)

Work done image

According to the first law of thermodynamics: image.

For an isothermal process: image.

image

Heat absorbed during this expansion is image

answered Nov 30, 2015 by Lucy Mentor
edited Nov 30, 2015 by Lucy

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