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Trigonometry - Arctan

0 votes

a= Arctan6/7 b= Arctan 1/2 c=Arctan1/4 Prove that 0

asked Dec 4, 2013 in TRIGONOMETRY by skylar Apprentice

1 Answer

0 votes

Given  a = Arctan(6/7)

a = tan^-1(0.8571)

a = 40.59

b = Arctan(1/2)

b = tan^-1(0.5)

= 26.56

c = Arctan(1/4)

c = tan^-1(0.25)

c = 14.03

i assume the question is a-(b+c) = 0

to prove a-(b+c) = 0

b+c = 26.56+14.03 = 40.59

a-(b+c) = 40.59-(40.59) = 0

answered Jan 27, 2014 by friend Mentor

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