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what's the axis of symetry, vertex, and graph y=2x^2+6x-1

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please graph, show the axis of symetry, and the vertex of y= 2x^2+6x-1

asked Dec 5, 2013 in GEOMETRY by linda Scholar

1 Answer

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Given y = 2x^2+6x-1

Compare it standard parabola equation is y = ax^2+bx+c

a = 2, b = 6, c = -1

Axis of symmetry is x = -b/2a

x = -6/2*2 = -6/4

Axis of symmetry is x = -3/2

substitute x value in equation then we get y.

y = 2(-3/2)^2+6(-3/2)-1

y = 9/2-9-1

y = -11/2

Vertex of given parabola is (-3/2,-11/2).

Graph of given parabola

answered Dec 26, 2013 by ashokavf Scholar

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