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(x+1) dy/dx= x (y^2+1)

0 votes

Solve by variable separation method.

asked Feb 18, 2014 in CALCULUS by futai Scholar

2 Answers

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Let us take integration on both sides

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answered Apr 8, 2014 by friend Mentor

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tan^-1 (y)= x - log (x+1) + c1

y = tan (x - log(x+1) + c1)

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Let us take integration on both sides

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Tan ^ -1 ( y ) = x - log ( x + 1 ) + c1

y =Tan [ x - log( x + 1) + c1].

 

answered Apr 8, 2014 by friend Mentor

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