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How do you solve an equation with two variables 2x^2 - 3xy +2y^2 = 2

0 votes
i've tried to complete the square.
asked Mar 11, 2014 in ALGEBRA 2 by dkinz Apprentice

1 Answer

0 votes

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The diophantine equation image

The term Diophantine Equation means that the solutions (x , y ) should be integer numbers.

Compare the above equation image.

A = 2 , B = -3, C = 2, D = 0, E = 0, F = -2.

Discriminant image

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So the above equation is elliptical.

Elliptical case

Since the ellipse is a closed figure, the number of solutions will be finite.

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For any value of x  there will be two values of y  except at the left and right extremes of the ellipse. In this case there will be only one value of y . To determine the location of the left and right extremes we should equal the square root to zero, so the previous expression returns only one value of y .

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So the values of x should be between the roots of this equation.

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Solutions

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answered Apr 18, 2014 by david Expert
edited Apr 18, 2014 by david

The value of y = (1/4) [3x - sqrt(16 - 7x2)] and the value of x = ±4/√7.

To determine the location of the left and right extremes we should equal the square root to zero, so the previous expression returns only one value of y .

Since sqrt(16 - 7x2) = sqrt[16 - 7(±4/√7)2] = sqrt[16 - 16] = 0.

The remaining y value is y= (1/4) 3x.

If x = 4/√7 then y = (1/4) [3 (4/√7)] ----> y = 3/√7.

If x = - 4/√7 then y = (1/4) [3 ( - 4/√7)] ----> y = - 3/√7.

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