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Magnitude of an electric field?

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What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 9.0g that has been charged to -3.0 nC?. 

A) 9.0 × 10^6 N/C B) 6.3 × 10^6 N/C C) 3.3 × 10^6 N/C D) 2.9 × 10^7 N/C 

asked Jul 15, 2014 in PHYSICS by anonymous

1 Answer

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Electrical field is force per charge ratio.

Given,

Mass of the sphere = 9 g = 9×10-3 kg

Charge, q = - 3 nC = -3×10-9 C

Calculate the weight of the sphere.

F = mg

    = (9×10-3) (9.81)

    = 0.08829 N

Calculate the magnitude of the electrical field ,

E = F / q

   = 0.08829 / -3×10-9

    = -2.9×107 N/C

Therefore, the option D is correct.

 

answered Jul 16, 2014 by bradely Mentor

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