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Summation for volume of a sphere?

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Hey trying to get this equation worked out for a bigger equations but I cant get the answer myself and need help ...

(4/3*π*1^3)+(4/3*π*2^3)+(4/3*π*3^3) = 150.796^3

How do you get it to work like easier summations such as this without the cubed radius

(4/3*π*1)+(4/3*π*2)+(4/3*π*3) = 25.132
Sigma 1->3 = nπ -> n=((3+1)3)/2
asked Aug 4, 2014 in PRECALCULUS by anonymous

1 Answer

0 votes

(4/3*π*13)+(4/3*π*23)+(4/3*π*33) = 150.7963

Take out the common factor

= (4/3*π) * (13+23+33)

We know that Sums of Powers of Integers :

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answered Aug 4, 2014 by casacop Expert

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