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trigonometric areas help!!!!!!!!!!!!

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What is the area of triangle ABC if angle A is 60 degrees, side b is 40 feet and side c is 20 feet?

asked Feb 26, 2013 in TRIGONOMETRY by rockstar Apprentice

2 Answers

0 votes

straight A equal 60 to the power of 0

b = 40

c = 20

Area of triangle  =1 over 2bc sinA

Substitute   the values in formula

                        =1 over 2(40) (20) sin60 to the power of 0

                       =1 over 2(40)(20) fraction numerator square root of 3 over denominator 2 end fraction     (Substitute sin60 to the power of 0= fraction numerator square root of 3 over denominator 2 end fraction)

                       =(400)fraction numerator square root of 3 over denominator 2 end fraction               (Simplify)

                       = (200)square root of 3                 (Simplify)

answered Mar 7, 2013 by hussy Rookie
0 votes

Here height c = 20 and b = 40 and A = 60°

The right angle triangle of the area is (1/2)(bh sinθ)

area = (1/2)(40)(20)sin(60°)

Trigonometry table in sin(60°) = 0.8660

area = (20)(20)(0.8660)

area = 346.4 square units.

There fore the area of triangle is 346.4 square units.

answered Mar 7, 2013 by richardson Scholar

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