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Multiple choice help

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To put the equation in standard form, what should you do first?
5x2 - 3y2 - 20x + 6y + 2 = 0
Select one:

 

asked Aug 23, 2014 in PRECALCULUS by swatttts Pupil

1 Answer

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Best answer

d is the answer.

5x2 - 20x - 3y2 + 6y +2 = 0

5(x2 - 4x) - 3(y2 - 2y) +2 = 0

To change the expression into a perfect square  add (half the x coefficient)² and (half the y - coeffient)² to each side of the expression.

Here x coefficient = - 4, so, (half the x coefficient)² = (- 4/2)2= 4.

Here y coefficient = - 2, so, (half the x coefficient)² = (- 2/2)2= 1.

Add 20 and - 3 to each side of the equation.

5(x2 - 4x + 4) - 3(y2 - 2y + 1)+2 = 0 + 20 - 3

5(x - 2)2 - 3y - 1)2 = - 2 + 17

5(x - 2)2 - 3(y - 1)2 = 15

(x - 2)2/3 - (y - 1)2/5= 1

answered Aug 23, 2014 by bradely Mentor
selected Aug 23, 2014 by swatttts

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