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Solve by finding the LCD?

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4/(x+6) = 1/(3x)
asked Dec 27, 2012 in PRE-ALGEBRA by dkinz Apprentice

1 Answer

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Given equation is 4/(x+6) = 1/(3x)

Subtract 1/(3x) from each side

4/(x+6) - 1/(3x) = 1/(3x) - 1/(3x)

4/(x+6) - 1/(3x) = 0

LCD of x+6 and 3x is (x+6)(3x)

4(3x) - 1(x+6)/(x+6)(3x) = 0

4(3x) - 1(x+6)= 0

12x - x - 6 = 0

11x - 6 = 0

11x = 6

x = 6 / 11

 

answered Dec 27, 2012 by ashokavf Scholar

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