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If RG = 7x+3, GQ = 3x+13, and RQ = 56,

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then find the value for x,RQ, and GQ. If AB= x+4, BC= 2x -10, and AC = 2x+1 then find the value AB,AC? 

 

 

asked Sep 11, 2014 in GEOMETRY by anonymous

1 Answer

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(1)RQ=RG+GQ

      =(7x+3)+(3x+13)

      =10x+16

RQ=10x+16 =56

      ⇒10x =40

      ⇒ x= 4

GQ= 3x+13

      = 3*4+13

      =12+13

      =25

 

(2) AC = AB+BC

2x+1 = (x+4) + (2x-10)

2x+1 = 3x -6

3x -2x = 1+6

x = 7

AB = x+4 = 7+4 =11

AC = 2x+1 = 2*7 +1

                   =14+1 =15

answered Sep 11, 2014 by friend Mentor

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