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A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest.

0 votes
a.) find the total kinetic energy after collision if the collision is elastic. b.) find the total kinetic energy after collision if the collision is completely inelastic.
asked Mar 8, 2013 in PHYSICS by anonymous Apprentice

1 Answer

+1 vote

Mass of the air-track glider ,ma=0.2 kg

Speed of the air-track glider ,v1=1.2 m/s

Mass of the bumps,mb=0.6 kg

Speed of the bumps ,v2=0

a)

an elastic collision conserves mechanical energy
KE = 1/2 ma* v1^2

Substitute 1.2 for v1 and 0.2 for ma

       = 1/2 0.200 (1.20)^2

       = 0.144 J
b)

Totally inelastic collisions conservation  of momentum
M1V1 + M2V2 = (M1+M2)V3
0.200(1.20) + 0.600(0) = 0.800(V3)
V3 = 0.300 m/s
so
KE = 1/2 m v^2 = 1/2 (0.800) (0.300)^2 = 0.036 J
notice that 3/4 of the original KE is lost in this collision

answered Mar 8, 2013 by bradely Mentor

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