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Calculus question Differentiate

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(1/y^2 - 3/y^4)(y+5y^3)

derivative-of-a-function

asked Oct 22, 2014 in CALCULUS by anonymous

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1 Answer

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The expression is (1/y² - 3y)(y+5y³)

= (1/y²)(y+5y³) - (3y)(y+5y³)

= 1/y + 5y - 3y² - 15y⁴

Differentiate with respect to y.

= -1/y² + 5 - 6y - 60y³

The differentiate of (1/y² - 3y)(y+5y³) = -1/y² + 5 - 6y - 60y³.

answered Oct 22, 2014 by casacop Expert

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