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Calculus Derivative Help PLEASE ANSWER?

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What is the derivative of (x^2-3x-4)/(x-2)? Thanks.

asked Nov 3, 2014 in CALCULUS by anonymous

1 Answer

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The function  (x2 - 3x - 4)/(x - 2)

Differentiating with respect to x.

Apply quotient rule in derivatives d/dx(u/v) = (vu' - uv')/v2

Apply the formulae d/dx(xn) = nxn-1

d/dx(constant) = 0

In this case u = x2 - 3x - 4, v = x - 2

u' = 2x - 3, v' = 1

Now the derivative is [(x - 2)(2x - 3) - (x2 - 3x - 4)(1)]/(x - 2)2

= (2x2 - 3x - 4x + 6 - x2 + 3x + 4)/(x - 2)2

= (x2 - 4x + 10)/(x - 2)2.

answered Nov 3, 2014 by david Expert

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