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Write an equation of the parabola y = a(x – h)2 + k that satisfies the conditions.

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Vertex: (-3, 1); Point on the graph: (0, -8)?

asked Nov 4, 2014 in PRECALCULUS by anonymous

1 Answer

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The vertex form of parabola is y = a(x - h)2 + k

Where (h, k) is vertex.

The parabola passes through (0, - 8).

Substitute (x, y) = (0, - 8) and (h, k) = (-3, 1) in y = a(x - h)2 + k.

- 8 = a[(0 - (- 3)]2 + 1

Solve for a.

- 8 = 9a + 1

9a = - 8 - 1

9a = - 9

a = - 1

Substitute a = -1 and (h, k) = (-3, 1) in y = a(x - h)2 + k.

Required equation y = - 1(x - ( - 3)]2 + 1.

answered Nov 4, 2014 by david Expert

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